jQuery通用的全局遍历方法$.each()用法实例
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2024-02-26
(PHP 5 >= 5.1.0)
pg_field_type_oid — Returns the type ID (OID) for the corresponding field number
说明
int pg_field_type_oid ( resource$result
, int $field_number
)
pg_field_type_oid() returns an integer containing the
OID of the base type of the given field_number in the
given PostgreSQL result resource.
You can get more information about the field type by querying PostgreSQL's pg_type system table using the OID obtained with this function. The PostgreSQL format_type() function will convert a type OID into an SQL standard type name.
Note:
If the field uses a PostgreSQL domain (rather than a basic type), it is the OID of the domain's underlying type that is returned, rather than the OID of the domain itself.
参数
result
PostgreSQL query result resource, returned by pg_query(), pg_query_params() or pg_execute() (among others).
field_number
Field number, starting from 0.
返回值
The OID of the field's base type. FALSE is returned on error.
范例
Example #1 Getting information about fields
<?php
$dbconn = pg_connect("dbname=publisher") or die("Could not connect");
// Assume 'title' is a varchar type
$res = pg_query($dbconn, "select title from authors where author = 'Orwell'");
echo "Title field type OID: ", pg_field_type_oid($res, 0);
?>
以上例程会输出：
Title field type OID: 1043
参见
pg_field_type() - 返回相应字段的类型名称 pg_field_prtlen() - 返回打印出来的长度 pg_field_name() - 返回字段的名字
